By J. Hayavadana

ISBN-10: 085709002X

ISBN-13: 9780857090027

Facts for cloth and clothing administration offers with the elemental rules of statistical equipment and their functions in fabric creation. this can be in fibre, yarn or textile manufacture and throughout any of the allied tactics resembling dyeing, printing and completing. This booklet is a perfect reference for cloth technologists and scholars

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**Extra info for Statistics for Textile and Apparel Management**

**Sample text**

Of persons 242 220 268 70 800 is remaining Calculation of average age of those retained. 5. In total the life of resistors were 281. Find the average life of those who have not failed. 4 Measures of central tendency 51 Example: In a spun silk factory there are 100 skilled, 250 semi-skilled and 150 unskilled workers. 5 m in 3 days by a skilled worker, 4 days by semi-skilled and 5 days by unskilled worker. After training of 2 years the semi-skilled workers are expected to become skilled workers and the unskilled workers become semi-skilled workers.

4. 5. Mean is rigidly defined. It is based on all items in the given distribution. It is least affected by fluctuations in the sample. It is easily understandable and simple in calculation. It can be subjected to algebraic treatment. Demerits are as follows: 1. It is greatly affected by the extreme items, and its usefulness as a “summary as a whole” may be considerably reduced. 2. When the distribution has open class, its computation is based on assumption and therefore may not be valid. 3. It can be determined by inspection as in the case of mode or median.

Divide by N is ∑f. Example: From the following data of the tpi of 60 yarns produced in a mill. Calculate the arithmetic mean. (X) tpi (f) Number of yarns N = ∑f = 60 20 8 30 12 40 20 50 10 60 6 70 4 Solution: f(x) 160 360 800 500 360 280 ∑f(X) = 2460 X = ∑fX / N = 2460 / 60 = 41 Short-cut method: Select an assumed mean as 40. 3 33 Correcting incorrect values Example: The GSM of 100 fabrics were found as 40. Later on it was discovered that an observation of 53 was misread as 83. Find the correct mean corresponding to the correct score.

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